x^2-14x-12=0

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Solution for x^2-14x-12=0 equation:


Simplifying
x2 + -14x + -12 = 0

Reorder the terms:
-12 + -14x + x2 = 0

Solving
-12 + -14x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '12' to each side of the equation.
-12 + -14x + 12 + x2 = 0 + 12

Reorder the terms:
-12 + 12 + -14x + x2 = 0 + 12

Combine like terms: -12 + 12 = 0
0 + -14x + x2 = 0 + 12
-14x + x2 = 0 + 12

Combine like terms: 0 + 12 = 12
-14x + x2 = 12

The x term is -14x.  Take half its coefficient (-7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
-14x + 49 + x2 = 12 + 49

Reorder the terms:
49 + -14x + x2 = 12 + 49

Combine like terms: 12 + 49 = 61
49 + -14x + x2 = 61

Factor a perfect square on the left side:
(x + -7)(x + -7) = 61

Calculate the square root of the right side: 7.810249676

Break this problem into two subproblems by setting 
(x + -7) equal to 7.810249676 and -7.810249676.

Subproblem 1

x + -7 = 7.810249676 Simplifying x + -7 = 7.810249676 Reorder the terms: -7 + x = 7.810249676 Solving -7 + x = 7.810249676 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + x = 7.810249676 + 7 Combine like terms: -7 + 7 = 0 0 + x = 7.810249676 + 7 x = 7.810249676 + 7 Combine like terms: 7.810249676 + 7 = 14.810249676 x = 14.810249676 Simplifying x = 14.810249676

Subproblem 2

x + -7 = -7.810249676 Simplifying x + -7 = -7.810249676 Reorder the terms: -7 + x = -7.810249676 Solving -7 + x = -7.810249676 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + x = -7.810249676 + 7 Combine like terms: -7 + 7 = 0 0 + x = -7.810249676 + 7 x = -7.810249676 + 7 Combine like terms: -7.810249676 + 7 = -0.810249676 x = -0.810249676 Simplifying x = -0.810249676

Solution

The solution to the problem is based on the solutions from the subproblems. x = {14.810249676, -0.810249676}

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